Research Space for Linear Algebra & Discrete Mathematics
(A∩C')∪(B∩C')∪A= ((A∪B)∩C')∪A= ((A∪B)∪A)∩(C'∪A)= (A∪B)∩(C'∪A)= A∪(B∩C')= A∪(B-C)
謝謝助教 thanks a lot.
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2 則留言:
(A∩C')∪(B∩C')∪A
= ((A∪B)∩C')∪A
= ((A∪B)∪A)∩(C'∪A)
= (A∪B)∩(C'∪A)
= A∪(B∩C')
= A∪(B-C)
謝謝助教 thanks a lot.
張貼留言