97輔大~線代4.4

T:V-->V' linear
T:1-1<=>ker(T)={0}

pf:
(<=)
設T(u)=T(v) =>
T(u)-T(v)=0 =>
T(u-v)=0 =>
u-v屬於ker(T)=>
u-v=0 =>
u=v

疑問:u-v=0表示承認0-->0, 0真的只會送到0嗎??這是定義嗎