Research Space for Linear Algebra & Discrete Mathematics
floor(x/3)+floor((x+1)/3)+floor((x+2)/3) --(*)令 x=3k+c, for some k in Z, c in Rif 0≦c＜1: (*) = k +k +k =3k =floor(x)if 1≦c＜2: (*) = k +k +(k+1) =3k+1 =floor(x)if 2≦c＜3: (*) = k +(k+1) +(k+1) =3k+2 =floor(x)
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請問 劃紅線
1 則留言:
floor(x/3)+floor((x+1)/3)+floor((x+2)/3) --(*)
令 x=3k+c, for some k in Z, c in R
if 0≦c＜1: (*) = k +k +k =3k =floor(x)
if 1≦c＜2: (*) = k +k +(k+1) =3k+1 =floor(x)
if 2≦c＜3: (*) = k +(k+1) +(k+1) =3k+2 =floor(x)
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