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麻煩助教了~感謝 ︿︿!!
2010-02-20
[線代] - 一些觀念
95中央 T or F
(f) Perspective projection is combined from the perspective and projection
transformations; the perspective projection is not linear transformation, but
perspective transformation is invertible.
→請問perspective transformation是什麼阿? Perspective projection?
(j) The columns of the change-of-coordinates matrix P are C-coordinate vectors of
C<-B
the vector in B.
→這題看不懂,後面那句到底是C轉B還B轉C~考試很怕英文不好會錯意
謝謝
(f) Perspective projection is combined from the perspective and projection
transformations; the perspective projection is not linear transformation, but
perspective transformation is invertible.
→請問perspective transformation是什麼阿? Perspective projection?
(j) The columns of the change-of-coordinates matrix P are C-coordinate vectors of
C<-B
the vector in B.
→這題看不懂,後面那句到底是C轉B還B轉C~考試很怕英文不好會錯意
謝謝
[離散] - 圖論
上課筆記有一題: n個點{1,2,3,.........,n}
1.simple graph 個數?
2.三角形123 有幾個?
3.所有三角形有幾個?
4.平均一個graph的三角形有幾個?
另外,98中山電機
1.How many ways can the undirected complete graph be oriented into a directed graph?
2.Given two selected vertices S and T, how many paths of length n-1 with distinct vertices
from vertex S to vertex T are contained in the graph?
我圖論算個數都不太會.....不知道怎麼想
麻煩助教了,謝謝
1.simple graph 個數?
2.三角形123 有幾個?
3.所有三角形有幾個?
4.平均一個graph的三角形有幾個?
另外,98中山電機
1.How many ways can the undirected complete graph be oriented into a directed graph?
2.Given two selected vertices S and T, how many paths of length n-1 with distinct vertices
from vertex S to vertex T are contained in the graph?
我圖論算個數都不太會.....不知道怎麼想
麻煩助教了,謝謝
2010-02-19
2010-02-18
[離散] - 排列組合
1.Determine the number of four-element subsets of S = {1,2 ,3,......,15}
contaun no consecutive integers.
2. (1+x^2+x^4)^5 , how many terms are there? (是不是只能展開看有幾項~?)
3. The nuver of partitions of {1,2,3,4,5} into three blocks is [5 3]^t = 25
The total number of functions f: {1,2,3,4,5} -> {1,2,3,4} with |f({1,2,3,4,5})| = 3
is ?
ans: 4 x 25 x6 (看不懂)
contaun no consecutive integers.
2. (1+x^2+x^4)^5 , how many terms are there? (是不是只能展開看有幾項~?)
3. The nuver of partitions of {1,2,3,4,5} into three blocks is [5 3]^t = 25
The total number of functions f: {1,2,3,4,5} -> {1,2,3,4} with |f({1,2,3,4,5})| = 3
is ?
ans: 4 x 25 x6 (看不懂)
[線代] 一題題目請益
A linear system Ax=b of m equations and n variables . State under what conditions will the linear system have solutions , a unique solution ,
and infinity many solutions ?
------------------------------------------------------------
請問這題是直接寫出3版課本的定理1-19嗎?!
還是說有其他需要補充的地方呢?!!
麻煩各位了~謝謝 !!!
and infinity many solutions ?
------------------------------------------------------------
請問這題是直接寫出3版課本的定理1-19嗎?!
還是說有其他需要補充的地方呢?!!
麻煩各位了~謝謝 !!!
2010-02-17
[離散]邏輯 if p then q else r
請問 if p then q else r
等價於(p->q)and(~p->r) 等價於 (p and q)or(~p and r)
最後那一個是怎樣推的呢 ?
等價於(p->q)and(~p->r) 等價於 (p and q)or(~p and r)
最後那一個是怎樣推的呢 ?
2010-02-15
[離散] 一些題庫
大家好, 新年快樂
問題一:
(97中興資管) How many strings of five decimal digitals which have exactly three digitals 9s?
答案是C5取3乘9平方, 解答意思似乎是選三個位置放9, 其餘位置的範圍為0~8有九個
請問它不用扣掉首項為零的strings嗎?
如..{00999,01999,...,08999, 09099,09199,...,09899, 09909,09919,...,09989, 09990,09991,...,09998}這些
問題二:請問後面的n-2代表什麼意思呢
問題三: (c)小題為什麼會有個係數3?
問題四: 下面的推導好像有錯..不知道在哪裡
謝謝
問題一:
(97中興資管) How many strings of five decimal digitals which have exactly three digitals 9s?
答案是C5取3乘9平方, 解答意思似乎是選三個位置放9, 其餘位置的範圍為0~8有九個
請問它不用扣掉首項為零的strings嗎?
如..{00999,01999,...,08999, 09099,09199,...,09899, 09909,09919,...,09989, 09990,09991,...,09998}這些
問題二:請問後面的n-2代表什麼意思呢
問題三: (c)小題為什麼會有個係數3?
問題四: 下面的推導好像有錯..不知道在哪裡
(p→q)∧[﹁q∧(rˇ﹁q)]
≡(p→q)∧[﹁q∧(q→r)]
≡[(p→q)∧(q→r)]∧﹁q
≡(p→r)∧﹁q
≡(﹁pˇr)∧﹁q
謝謝
2010-02-14
[線代]負定判斷
Q=[ 0 1 1 ]
[ 1 0 1 ]
[ 1 1 0 ]
Q on the subspace M={x: x1 + x2+ x3 =0}
is 正定 負定 不定?
請問這種是直接判斷Q是不是負定就好
還是要縮小定義域 檢查M的element在Q 會不會恆小於0
如果M的element在Q會恆小於0 可以說Q在M上負定嗎 ?
例如 取M的一組basis={[1,-1,0]^t,[1,0,-1]^t}
M中的任一vector可表成x=c1v1+c2v2
則x^tQx = -2c1^2-2c1c2 -2c2^2 = -2((c1-c2/2)^2+3c2^2/4) 恆小於0
所以可以說 Q 在 M負定嗎 ?
2010-02-13
[離散]Eular Formula證明
先令N表所有區域為成的邊數總和(涵無線區域及重複邊)
因為每個區域至少含三邊 所以 N>=3r
因為每個邊至多落在2個區域邊界上 所以N<=2e
請問為什麼不是剛好落在兩個region的邊界上 所以N=2e 呢 ... ?
我看老師的筆記 算圍成region邊數的方法
似乎是要繞一圈耶
x----y----z
像這樣只有一個無限區域圍成外面region的邊數似乎要算成4個@@
這樣圍成外面region 和圍成裡面region的邊數都是6
因為每個區域至少含三邊 所以 N>=3r
因為每個邊至多落在2個區域邊界上 所以N<=2e
請問為什麼不是剛好落在兩個region的邊界上 所以N=2e 呢 ... ?
我看老師的筆記 算圍成region邊數的方法
似乎是要繞一圈耶
x----y----z
像這樣只有一個無限區域圍成外面region的邊數似乎要算成4個@@
x
\
y---z
|\ |
| t |
| |
w---v
這樣圍成外面region 和圍成裡面region的邊數都是6
2010-02-12
2010-02-11
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