Find the probability that a family with five children does not have a boy,if the sexes of children are independent and if probability that the i th a boy is 0.51-(i / 100)
機率好難Q_Q
有勞助教解答了...
Research Space for Linear Algebra & Discrete Mathematics
2 則留言:
第 1 胎生男的機率為 0.51 - 0.01 = 0.5
第 2 胎生男的機率為 0.51 - 0.02 = 0.49
...
第 5 胎生男的機率為 0.51 - 0.05 = 0.46
所以生五個小孩全部都是女生的機率為
0.5 * 0.51 * 0.52 * 0.53 * 0.54
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