Research Space for Linear Algebra & Discrete Mathematics
<e^x, u1> = e-1<u1, u1> = 1<e^x, u2> = 積分在這裡= -e/2 + 3/2<u2, u2> = 1/12
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2 則留言:
<e^x, u1> = e-1
<u1, u1> = 1
<e^x, u2> = 積分在這裡= -e/2 + 3/2
<u2, u2> = 1/12
感謝~!!
張貼留言