A factory makes automobile parts. Each part has a code consisting of a digit,a letter,and a digit,with the digits disinct,such as 5C7,1O6,or 3Z0.Last week the factory made 8,000 parts.
Find the minimum number of parts that must have the same serial number.[96台大電機離散 14 .]
解答給D，但我覺得是C，理由如下:
8000 = 2340 + 2340 + 2340 + 980
Find the minimum number of parts that must have the same serial number.
最小的重複號碼我認為只有三組
ex: 位數為2，僅使用0~1編號，共14組
考慮如下;
(0 0) (0 0) (0 0) (0 0)
(0 1) (0 1) (0 1) (0 1)
(1 0) (1 0) (1 0)
(1 1) (1 1) (1 1)
Find the minimum number of parts that must have the same serial number.
>>三組
1 則留言:
the idea here is that there are 10*26*9=2340 types of code, so the minimum number of the parts that must have the same serial number should be ceiling(8000/2340)=4
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