Research Space for Linear Algebra & Discrete Mathematics
H_(2^(k+1))= 1 + 1/2 + ... + 1/2^k + 1/(2^k+1) + ... + 1/2^(k+1)= (1 + 1/2 + ... + 1/2^k) + [1/(2^k+1) + ...+ 1/2*2^k]= H_(2^k) + [1/(2^k+1) + 1/(2^k+2) + ... + 1/(2^k+2^k)]
不太懂耶上線寫到H_(2^(k+1)) = H_(2^k) + [1/(2^k+1) + 1/(2^k+2) + ... + 1/(2^k+2^k)]那這串[1/(2^k+1) + 1/(2^k+2) + ... + 1/(2^k+2^k)]是代表什麼意思??
這邊就只是把一串很長的數列加總拆成兩個部分而已, 就好像 1+2+3+4+5+6 = (1+2+3)+(4+5+6) 這樣
張貼留言
3 則留言:
H_(2^(k+1))
= 1 + 1/2 + ... + 1/2^k + 1/(2^k+1) + ... + 1/2^(k+1)
= (1 + 1/2 + ... + 1/2^k) + [1/(2^k+1) + ...+ 1/2*2^k]
= H_(2^k) + [1/(2^k+1) + 1/(2^k+2) + ... + 1/(2^k+2^k)]
不太懂耶
上線寫到H_(2^(k+1)) = H_(2^k) + [1/(2^k+1) + 1/(2^k+2) + ... + 1/(2^k+2^k)]
那這串[1/(2^k+1) + 1/(2^k+2) + ... + 1/(2^k+2^k)]是代表什麼意思??
這邊就只是把一串很長的數列加總拆成兩個部分而已, 就好像 1+2+3+4+5+6 = (1+2+3)+(4+5+6) 這樣
張貼留言