Research Space for Linear Algebra & Discrete Mathematics
1. 從第三行改成2 = 19 * 2 + 3 * 2 * (-6) = 19 * (2 - 3k) + 3 * (-12 + 19k)=> 3 * (-12 + 19k) = 2 (mod 19)=> x = -12 + 19k2. 作法改成同除以3再作即8x = 2 (mod 27)
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1 則留言:
1. 從第三行改成
2 = 19 * 2 + 3 * 2 * (-6)
= 19 * (2 - 3k) + 3 * (-12 + 19k)
=> 3 * (-12 + 19k) = 2 (mod 19)
=> x = -12 + 19k
2. 作法改成同除以3再作
即8x = 2 (mod 27)
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