Research Space for Linear Algebra & Discrete Mathematics
我會對中間那一列展開這樣展開二階就都是三角矩陣, 可得 det(A-xI) = 4x - x(1-x)(2-x) - 4(2-x)= 8(x-1) - x(1-x)(2-x)= (x-1)(8 - x(x-2))= -(x-1)(x^2 - 2x - 8)= -(x-1)(x-4)(x+2)
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我會對中間那一列展開
回覆刪除這樣展開二階就都是三角矩陣, 可得 det(A-xI) =
4x - x(1-x)(2-x) - 4(2-x)
= 8(x-1) - x(1-x)(2-x)
= (x-1)(8 - x(x-2))
= -(x-1)(x^2 - 2x - 8)
= -(x-1)(x-4)(x+2)
A tech writer who is passionate to write about streaming devices and its channel programs. Apart from my work, I am interested in music and sketching. Are you a person who needs updates about the new releases and is interested in tech blogs?
回覆刪除Have a look at my recent blogs:
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