Research Space for Linear Algebra & Discrete Mathematics
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第5題我用文氏圖也讀不出題目要的答案
1. I think a simple explanation here is enough2. Let A: a transmitted bit is actually 0B: a received bit is 1P(A|B)=p(A交集B)/p(B)=(0.3*p)/(0.3*p+0.7*(1-q))5. It it's obvious that there is something wrong with this statement after drawing out Venn's Diagram7. you can go check with a probability textbook; if you don't have any idea about it, it's better for you to have learned some probabilities here
1.他說正獨立跟相依 那我能直接用老師的公式嗎？ p(e1交集e2)=p(e1)p(e2) 說不是要說明一下，這個公式為何就是獨立相依
作者已經移除這則留言。
回覆刪除第5題我用文氏圖也讀不出題目要的答案
回覆刪除1. I think a simple explanation here is enough
回覆刪除2. Let A: a transmitted bit is actually 0
B: a received bit is 1
P(A|B)=p(A交集B)/p(B)
=(0.3*p)/(0.3*p+0.7*(1-q))
5. It it's obvious that there is something wrong with this statement after drawing out Venn's Diagram
7. you can go check with a probability textbook; if you don't have any idea about it, it's better for you to have learned some probabilities here